The signal mast on Sonora is a double track signal bridge.

What we want, for trains going up hill:

• T330 Normal aka “mainline” (block 320). Mainline green, Siding red.
• T330 Reversed aka “siding” (block 321). Mainline red, Siding green.

First I need to identify wires under the layout, there are likely 6 of them, 3 for each signal.

Apparently most of these use a common anode (e.g. http://www.sbsignal.com/ho-signals-and-systems.html).

[Update ⇒ 5, one is a common anode.]

Let’s say one common anode (aka positive, goes to + DC) and 2 cathode ("negatives").

Anode = +, Cathode = -.

Using a 1.5V battery, find 2 wires that light up one led. + is anode. If - on the 3rd wire lights the other led, that + side is a common anode.

Obviously that test implies all the LEDs are still working :-/

[Update ⇒ they were dead. Replaced them.]

We can wire the double track signal either using a DC/AC bus + Tortoise, or using the DCC rail polarity from the frog. Let’s call A the rail on the frog side, and B the continuous “outside” rail.

Turnout	Frog	Green Main	Red Main	Green Siding	Red Siding
Normal Main	Rail A	Frog-B = on	Frog-A = off	Frog-A = off	Frog-B = on
Reverse Siding	Rail B	Frog-B = off	Frog-A = on	Frog-A = on	Frog-B = off

For each signal, the common anode is connected to the frog. Each led cathode is connected to the rail A or B using a resistor, say 1k-10k depending on brightness.

Alternatively we can simplify wiring by using only one resistor per common anode, whichever is simpler to wire under the layout.

Typical red/green LED Vf is 1.8-2 V, 20 mA max.

Let’s say DCC = 12 V peak to peak; 12-2=10 V; 10 V / 10 mA = 1k Ω; 10 V / 20 mA = 500 Ω;

---